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This question already has an answer here:

Could you please help me, i would like to know how to calculate main and side pots in tournament, when stacks of players less then ante + one/all of this players on sb/bb.

For example:

Blinds 250/500, ante 50,


player1 30 - SB

player2 10 - BB

player3 5000

player4 2000


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marked as duplicate by Jeffrey Blake Mar 9 '13 at 5:59

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

up vote 5 down vote accepted

See here: How are side pots built? .

I don't think the rules about side pots will change if a player is so severely short stacked. In your particular case, I think it will be:

  • Main Pot: 40 (10 from each player, since player 2 has the fewest chips)
  • Side Pot 1: 60 (player 1 has 20 left, so players 3 and 4 also put 20 chips in. 3 x 20 = 60).
  • Side Pot 2: 40 (players 3 and 4 pay the whole ante, since they can afford it. So 20 each (the rest of 30 is in the main pot and in the 1st side pot) = 2 x 20 = 40).

All this is preflop, before any action.

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Wow, it's rare someone beats me to an answer while I'm typing it on :). Weird timing! – Cory Kendall Mar 6 '13 at 21:52
@CoryKendall I was actually surprised the question remained unaswered for 6 hours... – Radu Murzea Mar 6 '13 at 21:53

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