Tell me more ×
Poker Stack Exchange is a question and answer site for serious players and enthusiasts of poker. It's 100% free, no registration required.
up vote 4 down vote favorite

When multiple players go all-in during a hand in a tournament, and lose, how is their relative standing (5th, 6th, etc.) determined?

share|improve this question

1 Answer

up vote 9 down vote accepted

It is determined by their stack size prior to the hand starting.

share|improve this answer
1  
This is also true when playing multiple tables on the bubble in a hand-for-hand situation. So if there are two tables and player on each goes all in on the same hand, and they both bust, then the player with the shortest stack at the start of the hand is deemed to be the first person out of the two. – Lee Oades Jan 26 '12 at 11:32
@Adam Dymitruk: so what happens in the hypothetical case where the players had the same stack size prior to the hand? : ) – TacticalCoder Jan 26 '12 at 23:15
2  
The universe implodes, I'm guessing. – Adam Dymitruk Jan 26 '12 at 23:23
1  
If all players have the same amount of chips exactly on the bubble, they split the last prize according to the number of players with the same number of chips – amigal Jan 31 '12 at 16:35

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.