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In all poker hands not only the highest card determinates the better hand, all cards do. The best five card hand you can form is K:diamonds: J:diamonds: 8:diamonds: 6:diamonds: 2:diamonds: (which is the board). The best hand your opponent can form however is K:diamonds: J:diamonds: T:diamonds: 9:diamonds: 8:diamonds: So, while you both have the King and ...


In Poker you use the best 5 cards, so in this case no one wins...it's split. In fact, the only cards that could win here are an A, K, TJ, or pocket Q's. Knowing this, even if he had JJ or even QJ, it would still be split.


Player 2 wins, best 5-card hand rule: JJKKA


The highest 5 card hand, JJKKA beats JJKK4. The second four "doesn't play" because the pair of fours was superseded by TWO higher pairs. For the same reason, the two in player one's hand that creates a "matched pair" with the board, doesn't play.


No. The player with KQ would win the whole pot. The winner of the pot is the player who can make the best 5-card hand from the 7 possible cards -- 5 board cards plus their two hole cards. Player 1 has KQ, so his 7 cards are KKKQ642. Ignoring suits, the best possible hand here is KKKQ6, or trip kings with a queen kicker. Player 2 has K9, so his 7 cards ...


None of them. It will be a split.


The basic book is "how to read a hand" of Ed Miller. You can find the first here One most advanced and most general is "Let there be range" of South and Nguyen. You can find the last here Update: In "Harrington on online cash games : 6-max no-limit hold'em" there is a great chapter on hand reading.


When I hear tie breaker in poker, I think of the rule where the player with the most chips at the start of a hand ranks higher in a tournament when two or more players are eliminated in the same hand of a tournament. When in comes to the hands themselves, there is no such thing as a tie breaker. There are only two cases: 1) There is a tie -> split pot 2) ...


1). In this case, the kicker determines the winner. If the kicker is also the same, then the 2 players will split the pot. 2). In this case, it will be a split pot because, in poker, no suit is "better" or higher-ranked than another. 3). I think you mean a Royal Flush, which is, by definition, unbeatable. This is also a split pot. Like I said above: no ...


first of all, you didn't get the same hole cards, you got 7,4 and 7,3 Given two cards I think chance that neither card is the same rank would be 44/52 * 43/51 //in both situations we don't want a 7 of aces, hearts, clubs, or spades The chance that you get one of the cards the same or two cards the same is 1 - (44/52 *43/51) //the same thing as ...


If no one uses any cards in their hands, everyone "plays the board." Then everyone (that is left after the betting) splits the pot. The way to lose in this scenario is if someone bets and you fold. The "usual" way to win is that one or both of your cards represents an improvement on the board. In this case, if you had JT, you would make a AKQJT straight, ...


Nothing is random. Shuffles are not random especially on a computer, when it really comes down to it is all just cause and effect. However things are random in the sense that they are statistically random, and in theory random in a practical sense for the game of poker (or any other card game). Now there are holes in randomness with poker. In describing ...


You can tell the folks outright next time that in standard Hold 'Em, only the best 5 cards are playable in any one player's hand. In this case, the board is showing the best 5 cards (Aces and Kings with a Queen kicker), as neither player 1 nor player 2 can make a better 5 card hand than what is showing on the board.


How many ways can a 5-card draw-poker hand be dealt? In order to calculate the number of ways that a hand can be dealt, meaning that the order of the cards is significant, you need to multiply the possible number of cards at each step together. For a particular hand (meaning 5 specific cards), when the first card is dealt, you have 5 possible cards ...


I think your first question is asking, "How many ways can one be dealt 5 consecutive cards from a standard deck of 52 cards with the order of cards being distinct hands?" That is to say, a hand with the first card is Ace-of-spades then 2-of-spades then 3 other cards is distinct from being dealt first the 2-of-spades, next the Ace-of-spades, then the 3 other ...


To calculate all the 5 Card draw poker hands that exist you have to calculate 51! / 47! or explicite way 52 x 51 x 50 x 49 x 48 = 311,875,200 Now you need to know that for poker it doesn't matter wheter you have spades or clubs or whatever color. So in terms of value there are less hands. But that's the number of different hands you can have. What do ...

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