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Just from the top of my head I would say: I think Radu Murea's calculations are pretty ok, however I think that it really is mandatory to calculate that someone else can receive the 2nd card that could make your pair. You could do it in 2 steps: What is the chance to receive a pocket if you were dealt 2 cards after each other: First we receive any card ...


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I assume the value n is reasonable for a poker table (n = [2, 10]). In this case, it won't be relevant for the result. You start with 52 cards. You give the first player a card. The probability that the second card you give him has the same rank so that he'll get a pocket pair is: 3 / 51 (the 3 cards of the same rank that remained out of the remaining ...



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