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Based on your calculations... If you hold 4 cards (A to 4), you will ALWAYS make a pair? Estimate with 3/50 * 5 instead of the annoyingly similar fractions: (3/50 * 5) * 4 = 60/50 !? ===---=== The reason you won't get the right answer this way even though I can see the logic in your math is because of "double counting". You think the chance of hitting the ...


3

if I hold two different cards, what's the probability I get a pair at river? Probabilities computation can quickly get very complicated and you need to be very precise in what you want to exactly compute. What if the board comes with a pair in it? Do you consider that "getting a pair at river" or do you only want to know the probability of making a ...



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