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Without taking into account the fact that the very act of seeing the flop with one or several other player(s) influence the distribution of the flop (*), here's one way how you could compute these odds: you have C(50,3) possible flops: that is 19 600 flops out of these there are 48 cases where you'll improve directly to quads, so the probability to flop ...


I just have to add another answer to this question. I added it as another answer as opposed to a comment. I hope that's good etiquette, if not I apologize. The previous answer is "correct" in the purely mathematical and pedantic sense. There are lots of answers like the above so I'm not sure I'm adding anything. But, that is not how I actually calculate ...

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