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I assume the value n is reasonable for a poker table (n = [2, 10]). In this case, it won't be relevant for the result. You start with 52 cards. You give the first player a card. The probability that the second card you give him has the same rank so that he'll get a pocket pair is: 3 / 51 (the 3 cards of the same rank that remained out of the remaining ...

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