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5

Judging from what you wrote in the question, I think you are misunderstanding a few concepts here. First, math is math. Math doesn't care if you play poker, running, feeding your dog or doing something else. Math's laws are universal. This means that the math will have the same precision both in the heat of the battle and after the session is over and you ...


5

This is a binomial distribution: either you miss the flop or you don't. If your probability to NOT miss is .32, then your probability to miss is 1 - .32 = .68. Your number of trials is 22. The expected number of missing is 22 * .68 = 14.96. The variance of the binomial distribution is np(1-p). In your case, 22*.68*(1-.68) = 4.7872. The standard deviation ...


4

If such a player is approximating a game-theoretic-optimal (GTO) strategy, then they are essentially putting their opponent in a situation where it doesn't matter what they do. In other words, whatever information you believe you could glean from their play will not help you alter their expectation (i.e., reduce their expectation while increasing yours). ...


2

This information is not supposed to be public because no player would want to have their playstyle completely analyzed. Something you can do is approach players directly(maybe via forums like http://www.pokerstrategy.com/forum/) and ask is someone is willing to share his/her stats with you. I doubt that any pros would ever do that but if you explain why you ...


2

There's a 23.30% chance the other players have one of {66+, A7+}. Yes, there is an easy way to calculate the chance of a dominating hand behind you. You can use a program like ProPokerTools Odds Oracle to model the scenario and determine the probabilities. There is a free trial available. Below is a screenshot of the calculation as well as the log file. ...


1

I assume the value n is reasonable for a poker table (n = [2, 10]). In this case, it won't be relevant for the result. You start with 52 cards. You give the first player a card. The probability that the second card you give him has the same rank so that he'll get a pocket pair is: 3 / 51 (the 3 cards of the same rank that remained out of the remaining ...


1

sharkscope.com lets you search for stats of some famous players, you can check it. Dont try blindly to copy/achieve that stats, your play depends on your opponent tendencies, your goal is to have profit, therefore you have to consider your opponent tendencies to play. Heads Up especially is very "wild" and your decisions vary a lot depending on your ...


1

This is a fairly straightforward statistics question. You should look into the z-score for further details. If we assume your results against this opponent follows a normal distribution, the Excel formula to answer your question would be: =1-NORMDIST(X, Y * A / 100, Z * SQRT(A / 100), TRUE) That's the probability your opponent will be ahead at least X ...


1

I'm not exactly what sure what you're talking about when you mention "stats". Playing profitable poker comes down to implementing two concepts: Identifying your opponents strategy. Implementing the best response. The first point is primarily improved through experience. As you play more poker, you will more easily be able to identify what your opponent ...


1

TL;DR Given a flush on the board, five players will split 19.7% of the time, or about once every 5 hands. Given a fresh deal, the deal will come up with a flush showing and a five-way split 0.0389% of the time, or once every 2,569 hands. Some general probabilities Overall odds that none of the five players have a given suit (say, hearts): comb(39,10) / ...


1

I think the real question here is with a 5 card flush on the board what is the chance that out of 5 players none have one of the remaining 8 flush cards? The answer is 12.3% The odds of player one’s first card is not a flush suit is 39 of the remaining 47. We can see 5 cards, so 52-5 = 47 available cards. Of those 47 there are eight flush cards remaining so ...



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