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5

This is a binomial distribution: either you miss the flop or you don't. If your probability to NOT miss is .32, then your probability to miss is 1 - .32 = .68. Your number of trials is 22. The expected number of missing is 22 * .68 = 14.96. The variance of the binomial distribution is np(1-p). In your case, 22*.68*(1-.68) = 4.7872. The standard deviation ...


5

If such a player is approximating a game-theoretic-optimal (GTO) strategy, then they are essentially putting their opponent in a situation where it doesn't matter what they do. In other words, whatever information you believe you could glean from their play will not help you alter their expectation (i.e., reduce their expectation while increasing yours). ...


5

Judging from what you wrote in the question, I think you are misunderstanding a few concepts here. First, math is math. Math doesn't care if you play poker, running, feeding your dog or doing something else. Math's laws are universal. This means that the math will have the same precision both in the heat of the battle and after the session is over and you ...


3

This is likely to be very situation dependent. There is however, a section in the PokerTracker tool that analyses the range of common actions that players have taken, (eg. Cbet flop, fold to flop Cbet, 3bet stats, aggression stats, etc.), and gives a broad estimate of how often profitable players are taking those actions, whilst comparing your stats ...


3

There are five board cards in hold'em. Since you start with two known cards, there are 50 unknown. That means there are 50x49x48x47x46 ways the board can come. Since the order of the cards on the board doesn't matter, divide that by the number of ways 5 cards can be arranged (120), that's 2118760 total distinct boards. There are 47x46/2 of those boards that ...


2

There's a 23.30% chance the other players have one of {66+, A7+}. Yes, there is an easy way to calculate the chance of a dominating hand behind you. You can use a program like ProPokerTools Odds Oracle to model the scenario and determine the probabilities. There is a free trial available. Below is a screenshot of the calculation as well as the log file. ...


1

I assume the value n is reasonable for a poker table (n = [2, 10]). In this case, it won't be relevant for the result. You start with 52 cards. You give the first player a card. The probability that the second card you give him has the same rank so that he'll get a pocket pair is: 3 / 51 (the 3 cards of the same rank that remained out of the remaining ...


1

sharkscope.com lets you search for stats of some famous players, you can check it. Dont try blindly to copy/achieve that stats, your play depends on your opponent tendencies, your goal is to have profit, therefore you have to consider your opponent tendencies to play. Heads Up especially is very "wild" and your decisions vary a lot depending on your ...


1

This is a fairly straightforward statistics question. You should look into the z-score for further details. If we assume your results against this opponent follows a normal distribution, the Excel formula to answer your question would be: =1-NORMDIST(X, Y * A / 100, Z * SQRT(A / 100), TRUE) That's the probability your opponent will be ahead at least X ...



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