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(Edit: Please credit this shortcut to Phil Gordon as he is the one who came up with it and shared it with the poker world.)

A poker math geek gave me the following formula to use as an estimation.

Let's say you have 55:

1. Work out how many pairs are higher than your pair - 66, 77, 88, 99, 10, JJ, QQ, KK, AA = 9 pairs left

2. Count how many players are left = 8

3. Multiply higher pairs by players left and divide by 2

So in the above example, with 55 and 8 players left:

(9 x 8) / 2 = 36% chance of at least one of the remaining players having a higher pocket pair

Say you have 99 on the button and it's folded to you:

1. 5 pairs left
2. 2 players left
3. (5 x 2) / 2 = 5% chance of at least one of the remaining players having a higher pocket pair

A poker math geek gave me the following formula to use as an estimation.

(Edit: The credit for this shortcut goes to Phil Gordon and is known as the Gordon Pair Principle.)

Let's say you have 55:

1. Work out how many pairs are higher than your pair - 66, 77, 88, 99, 10, JJ, QQ, KK, AA = 9 pairs left

2. Count how many players are left = 8

3. Multiply higher pairs by players left and divide by 2

So in the above example, with 55 and 8 players left:

(9 x 8) / 2 = 36% chance of at least one of the remaining players having a higher pocket pair

Say you have 99 on the button and it's folded to you:

1. 5 pairs left
2. 2 players left
3. (5 x 2) / 2 = 5% chance of at least one of the remaining players having a higher pocket pair

A poker math geek gave me the following formula to use as an estimation.

Let's say you have 55:

1. Work out how many pairs are higher than your pair - 66, 77, 88, 99, 10, JJ, QQ, KK, AA = 9 pairs left

2. Count how many players are left = 8

3. Multiply higher pairs by players left and divide by 2

So in the above example, with 55 and 8 players left:

(9 x 8) / 2 = 36% chance of at least one of the remaining players having a higher pocket pair

Say you have 99 on the button and it's folded to you:

1. 5 pairs left
2. 2 players left
3. (5 x 2) / 2 = 5% chance of at least one of the remaining players having a higher pocket pair

(Edit: Please credit this shortcut to Phil Gordon as he is the one who came up with it and shared it with the poker world.)

A poker math geek gave me the following formula to use as an estimation.

Let's say you have 55:

1. Work out how many pairs are higher than your pair - 66, 77, 88, 99, 10, JJ, QQ, KK, AA = 9 pairs left

2. Count how many players are left = 8

3. Multiply higher pairs by players left and divide by 2

So in the above example, with 55 and 8 players left:

(9 x 8) / 2 = 36% chance of at least one of the remaining players having a higher pocket pair

Say you have 99 on the button and it's folded to you:

1. 5 pairs left
2. 2 players left
3. (5 x 2) / 2 = 5% chance of at least one of the remaining players having a higher pocket pair

A poker math geek gave me the following formula to use as an estimation.

You have 55 UTG

1. work out how many pairs are left 66 77 88 99 10 JJ QQ KK AA = 9 pairs left

2. how many players are left = 8

3. divide 2

9x8=72 / 2 = 36% chance of someone waking up with a higher PP

You have 99 BTN

1. 5 pairs left
2. 2 players left
3. divide 2 5x2=10 /2 = 5% chance of someone waking up with a higher PP

A poker math geek gave me the following formula to use as an estimation.

Let's say you have 55:

1. Work out how many pairs are higher than your pair - 66, 77, 88, 99, 10, JJ, QQ, KK, AA = 9 pairs left

2. Count how many players are left = 8

3. Multiply higher pairs by players left and divide by 2

So in the above example, with 55 and 8 players left:

(9 x 8) / 2 = 36% chance of at least one of the remaining players having a higher pocket pair

Say you have 99 on the button and it's folded to you:

1. 5 pairs left
2. 2 players left
3. (5 x 2) / 2 = 5% chance of at least one of the remaining players having a higher pocket pair