I am hosting a home game (NL Texas Hold'em sit N go), and would like to make sure we get all the rules right, but there is one situation that I'm having trouble with. What is the minimum raise after an all-in?
I think that there are three cases for an all-in:
All-in is less than the current bet
All-in is at least the current bet, but less than a minimum raise
All-in is at least a minimum raise
The first case clearly doesn't change the minimum raise and the third case clearly does; the second case is the one that I am uncertain about.
Suppose we have the following bets after the flop:
Player 1: Bets 200
Player 2: Raises to 600
Player 3: All-in
Player 4: Raise
I understand that the all-in (for < 1000 chips) does not allow Player 2 to re-raise unless there is another raise between them. What I don't know is how much Player 4 must bet to meet a minimum raise.
Situation 1: Suppose Player 3 had 700 chips. Is Player 4 able to raise to 1000 (calculated by ignoring the all-in), do they need to raise to 1100 (adding the previous minimum raise of 400 to the all-in amount). I doubt they'd be able to raise by only 700-600 = 100 chips
.
Suppose Player 3 had 999 chips. Is Player 4 able to re-open betting by raising to 1000, or would they need to raise to 1399, or maybe 1398?
My guess is that Player 4 can always raise to 1000, if the all-in was less than a minimum raise, but I would like some verification before I host the game.