If one player is holding a jack and a three and the other player is holding a jack and an ace and the cards on the table are showing a jack, a three, two 7's and a ten. The first player then has a pair of jacks, a pair of three's and a pair of 7's on the table. The second player has a pair of jacks, and the same two 7's on the table, with an ace high. They both have a pair of jacks and a pair of 7's but the first player also has a pair of three's, which should trump the ace high. Who has the winning hand?