I'm trying to understand as many pot scenarios as I can, and this one is troubling me.


Can someone explain to me what would happen in this scenario?

If needed, increase the bet amount of Player 7 so they have bet high enough that they'll get some of their money back (I could have set it at 100, but the graph would have looked silly).

Thank you!

2 Answers 2


Andrew's answer is correct, and is an example of the bottom-up approach typically taught to casino dealers. Another way to look at it is top-down from the highest bet (sometimes this is easier for a computer):

  1. Nobody matched player 7's last $3, so he is refunded those.
  2. At the $4 - $7 level, players 1..3 split $13: $3 from each of them, $1 from player 5, and $3 from player 7.
  3. All remaining $28 is split among players 1..4.
  4. Players 5,6,8,9 get nothing, because all of their bets are covered by players with better hands.
  • That's such a relief, because that's how I coded it! Thank you so much for your response. I'll accept this is the answer as you wrote it in a computer-programmer's-mind way :) Commented Apr 21, 2022 at 9:19

Players 1-3 stand to win up to 7, while Player 4 stands only to win up to 4.

Player 7 will be returned 3 since only 7 is required to call the all-in.

The main pot (28) will be split between Players 1-4. The side pot (13) will be split between Players 1-3.

  • Thank you very much for answering my question. I've accepted the other answer as it was framed in a way that made it easier for me to understand. I really appreciate your time! Commented Apr 21, 2022 at 9:20

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