When multiple players go all-in during a hand in a tournament, and lose, how is their relative standing (5th, 6th, etc.) determined?

1 Answer 1


It is determined by their stack size prior to the hand starting.

  • 1
    This is also true when playing multiple tables on the bubble in a hand-for-hand situation. So if there are two tables and player on each goes all in on the same hand, and they both bust, then the player with the shortest stack at the start of the hand is deemed to be the first person out of the two.
    – Lee Oades
    Commented Jan 26, 2012 at 11:32
  • @Adam Dymitruk: so what happens in the hypothetical case where the players had the same stack size prior to the hand? : ) Commented Jan 26, 2012 at 23:15
  • 2
    The universe implodes, I'm guessing. Commented Jan 26, 2012 at 23:23
  • 2
    If all players have the same amount of chips exactly on the bubble, they split the last prize according to the number of players with the same number of chips
    – amigal
    Commented Jan 31, 2012 at 16:35

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