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What are the odds of getting quadded when you have the highest full house on the table? I would reckon it's very rare, but I have done it once to an opponent.

2

I have seen it on TV a few times

Based on hand independent it is 0.000256 (quad) * 0.0017 (boat) = 0.00000044

From the boat there are 45 cards out and need to match the pair on the board
So the odds of getting quadded are:
(2/2) / (45/2) = 0.00101 = 0.1%
Which also = 2/45 * 1/44

Highest or lower boat is immaterial. Quads beat a full house.

| improve this answer | |
  • What about a board like AKKKx and you hold an ace? The risk of someone holding a K is much higher than that. – J.-E. Pin Mar 26 '16 at 19:11
  • @J.-E.Pin OK, what about a board like AKKKx? You are welcome to run those numbers. I just don't think OP would have asked the question in that manner if the board tripped. A lone ace would not be the highest full house on that table. – paparazzo Mar 26 '16 at 19:39

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