What are the odds of getting quadded when you have the highest full house on the table? I would reckon it's very rare, but I have done it once to an opponent.
I have seen it on TV a few times
Based on hand independent it is 0.000256 (quad) * 0.0017 (boat) = 0.00000044
From the boat there are 45 cards out and need to match the pair on the board
So the odds of getting quadded are:
(2/2) / (45/2) = 0.00101 = 0.1%
Which also = 2/45 * 1/44
Highest or lower boat is immaterial. Quads beat a full house.