This question already has an answer here:
Ratio method: I compare reward to risk (Rew:Risk) e.g. 3 To 1 (that might be 90 : 30, I refer to 30 as a constant later just for this example) My odds of hitting a hand is 33 %, hence 2 To 1
hand odds < pot odds ... call in abc poker
my question: how do i explain that if I have higher pot odds that i should call? These ratios work in this example like that on average from 3 games I win 1 of them, for those two losses I lose 1*some constant and for a win I win 3 times more than 1*constant, so on average from those 3 games my bankroll was boosted (bottom line) by 1*constant, is that correct?
In percentage method: I calc from those pot odds how much of the whole pot is mine... so from pot odds 3:1, mine is 1/4 = 25 %. Then I compare it with my pot equity (chances to win and also the amount of pot I win on average from this hand). If the percentage of my hand odds is higher, for example 33 %, then I on average win 33 % of the pot every time I play a hand like this and therefore I get back those 25 % of the pot invested by me counted from pot odds and plus being better than break-even by 8 %.
Is the whole thing I've tried to explain, correct?
Every book and every site covering poker "explain" this without actually explaining why this work (the comparison of hand and pot odds in either ratio or percentage method) and these are the only explanations I have been able to come up with.