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No, you need to multiply the probabilities. Assuming your numbers are correct, it would be P(flopped set) = P(pocket pair) * P(flop the third) P = 0.0588 * 0.1078 = .0063 So without other knowledge, the chance of getting a flopped set on any deal is a bit better than 1/2 of 1%. Another way to look at this is that the pocket pairs should arrive about once ...


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This one is difficult for me to calculate directly. Any suit can be the matching one, and any pair of seats can have the matched suits. So I just tried Monte Carlo. For two handed, the problem is simple. There are only 4 cards dealt, so the 2nd, 3rd, and 4th have to match the suit of the first one dealt. P = 1 * (12/51) * (11/50) * (10/49) = 0.0106 So it'...


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