No, you need to multiply the probabilities. Assuming your numbers are correct, it would be P(flopped set) = P(pocket pair) * P(flop the third)
P = 0.0588 * 0.1078 = .0063
So without other knowledge, the chance of getting a flopped set on any deal is a bit better than 1/2 of 1%.
Another way to look at this is that the pocket pairs should arrive about once ...
This one is difficult for me to calculate directly. Any suit can be the matching one, and any pair of seats can have the matched suits. So I just tried Monte Carlo.
For two handed, the problem is simple. There are only 4 cards dealt, so the 2nd, 3rd, and 4th have to match the suit of the first one dealt.
P = 1 * (12/51) * (11/50) * (10/49) = 0.0106