BowlOfRed
• Member for 7 years
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• San Francisco Bay Area

Depends on the rules in use. Two common sets are Roberts rules and Tournament Directors Association (TDA) rules. From Roberts Rules: IRREGULARITIES: If the dealer prematurely deals any cards ...

Typically, you "race" for the chips. Players get a card for any chips left over. Those chips are then colored up and are paid out based on high card. You cannot be eliminated this way. If you don'...

The odds of not being dealt an ace in a 2-card hand is the the odds of being dealt two non-aces. There are 48 non-aces in the deck, so this is (48/52) * (47/51), or 85% for one hand. The odds of it ...

I don't know what the factor of 6 is for in your first calculation. If you have a particular hole pair with a difference of four (say 6♣T⋄), then your analysis (without the factor of 6) for making a ...

Not sure the best way to calculate this, but I did a brute-force count. I examined if any 2-card hands when added to the 2598960 possible 5-card boards formed a straight. Some of these 2-card hands ...

Tournaments will have a targeted time, but may generate a winner before or after that point based on how the participants play. You're not going to guarantee a stopping point to the minute. I suspect ...

Was it seven cards drawn from the deck with no replacements? There are 52 choose 7 different 7-card combinations from a standard deck. In one suit, there are 8 different 7-card straights possible. ...

Azimut's speculation is correct. For a bit more detail: There are 15 cards from the hole cards and flop that are unavailable, leaving 37 possible remaining cards for 666 possible turn/river ...

Your hole cards are chosen at random from the full deck. Given any card picked as the first, you will have 51 remaining choices from the deck for the second card. Out of those 51 remaining, 12 will ...

This one is difficult for me to calculate directly. Any suit can be the matching one, and any pair of seats can have the matched suits. So I just tried Monte Carlo. For two handed, the problem is ...

No, you need to multiply the probabilities. Assuming your numbers are correct, it would be P(flopped set) = P(pocket pair) * P(flop the third) P = 0.0588 * 0.1078 = .0063 So without other knowledge, ...

Not every hand has to have both blinds. In some games, when the BB from the previous hand leaves the table, the SB becomes dealer and there is no SB for the next hand. I think that's what you're ...

I coded some python to generate every hand. As it seems to work okay for a regular deck (13 ranks, 4 suits), I think I can trust the numbers. For comparison, here's what it says for a regular deck (...

Note that your figure of 43.8% for a pair means "chance for a hand that is worth exactly one pair". So it excludes both better and worse hands. Some hands with a pair in them aren't even ...

Sklansky's Fundamental Theorem of Poker implies that if I see opponents hands, I should not bet in case my hand is not the best. I disagree. I think it doesn't say "you shouldn't bet". It ...

One possibility: Take the shuffled deck, add a timestamp, create a cryptographic hash of it. Record both on your site. Display the hash during the hand. Honestly, since you can create the deck ...